3.10.74 \(\int \frac {(A+B x) (d+e x)^3}{a+b x} \, dx\)

Optimal. Leaf size=123 \[ \frac {(A b-a B) (b d-a e)^3 \log (a+b x)}{b^5}+\frac {e x (A b-a B) (b d-a e)^2}{b^4}+\frac {(d+e x)^2 (A b-a B) (b d-a e)}{2 b^3}+\frac {(d+e x)^3 (A b-a B)}{3 b^2}+\frac {B (d+e x)^4}{4 b e} \]

________________________________________________________________________________________

Rubi [A]  time = 0.08, antiderivative size = 123, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.050, Rules used = {77} \begin {gather*} \frac {(d+e x)^3 (A b-a B)}{3 b^2}+\frac {(d+e x)^2 (A b-a B) (b d-a e)}{2 b^3}+\frac {e x (A b-a B) (b d-a e)^2}{b^4}+\frac {(A b-a B) (b d-a e)^3 \log (a+b x)}{b^5}+\frac {B (d+e x)^4}{4 b e} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[((A + B*x)*(d + e*x)^3)/(a + b*x),x]

[Out]

((A*b - a*B)*e*(b*d - a*e)^2*x)/b^4 + ((A*b - a*B)*(b*d - a*e)*(d + e*x)^2)/(2*b^3) + ((A*b - a*B)*(d + e*x)^3
)/(3*b^2) + (B*(d + e*x)^4)/(4*b*e) + ((A*b - a*B)*(b*d - a*e)^3*Log[a + b*x])/b^5

Rule 77

Int[((a_.) + (b_.)*(x_))*((c_) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Int[ExpandIntegran
d[(a + b*x)*(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, n}, x] && NeQ[b*c - a*d, 0] && ((ILtQ[
n, 0] && ILtQ[p, 0]) || EqQ[p, 1] || (IGtQ[p, 0] && ( !IntegerQ[n] || LeQ[9*p + 5*(n + 2), 0] || GeQ[n + p + 1
, 0] || (GeQ[n + p + 2, 0] && RationalQ[a, b, c, d, e, f]))))

Rubi steps

\begin {align*} \int \frac {(A+B x) (d+e x)^3}{a+b x} \, dx &=\int \left (\frac {(A b-a B) e (b d-a e)^2}{b^4}+\frac {(A b-a B) (b d-a e)^3}{b^4 (a+b x)}+\frac {(A b-a B) e (b d-a e) (d+e x)}{b^3}+\frac {(A b-a B) e (d+e x)^2}{b^2}+\frac {B (d+e x)^3}{b}\right ) \, dx\\ &=\frac {(A b-a B) e (b d-a e)^2 x}{b^4}+\frac {(A b-a B) (b d-a e) (d+e x)^2}{2 b^3}+\frac {(A b-a B) (d+e x)^3}{3 b^2}+\frac {B (d+e x)^4}{4 b e}+\frac {(A b-a B) (b d-a e)^3 \log (a+b x)}{b^5}\\ \end {align*}

________________________________________________________________________________________

Mathematica [A]  time = 0.12, size = 169, normalized size = 1.37 \begin {gather*} \frac {b x \left (-12 a^3 B e^3+6 a^2 b e^2 (2 A e+6 B d+B e x)-2 a b^2 e \left (3 A e (6 d+e x)+B \left (18 d^2+9 d e x+2 e^2 x^2\right )\right )+b^3 \left (2 A e \left (18 d^2+9 d e x+2 e^2 x^2\right )+3 B \left (4 d^3+6 d^2 e x+4 d e^2 x^2+e^3 x^3\right )\right )\right )+12 (A b-a B) (b d-a e)^3 \log (a+b x)}{12 b^5} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[((A + B*x)*(d + e*x)^3)/(a + b*x),x]

[Out]

(b*x*(-12*a^3*B*e^3 + 6*a^2*b*e^2*(6*B*d + 2*A*e + B*e*x) - 2*a*b^2*e*(3*A*e*(6*d + e*x) + B*(18*d^2 + 9*d*e*x
+ 2*e^2*x^2)) + b^3*(2*A*e*(18*d^2 + 9*d*e*x + 2*e^2*x^2) + 3*B*(4*d^3 + 6*d^2*e*x + 4*d*e^2*x^2 + e^3*x^3)))
+ 12*(A*b - a*B)*(b*d - a*e)^3*Log[a + b*x])/(12*b^5)

________________________________________________________________________________________

IntegrateAlgebraic [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {(A+B x) (d+e x)^3}{a+b x} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

IntegrateAlgebraic[((A + B*x)*(d + e*x)^3)/(a + b*x),x]

[Out]

IntegrateAlgebraic[((A + B*x)*(d + e*x)^3)/(a + b*x), x]

________________________________________________________________________________________

fricas [B]  time = 1.06, size = 269, normalized size = 2.19 \begin {gather*} \frac {3 \, B b^{4} e^{3} x^{4} + 4 \, {\left (3 \, B b^{4} d e^{2} - {\left (B a b^{3} - A b^{4}\right )} e^{3}\right )} x^{3} + 6 \, {\left (3 \, B b^{4} d^{2} e - 3 \, {\left (B a b^{3} - A b^{4}\right )} d e^{2} + {\left (B a^{2} b^{2} - A a b^{3}\right )} e^{3}\right )} x^{2} + 12 \, {\left (B b^{4} d^{3} - 3 \, {\left (B a b^{3} - A b^{4}\right )} d^{2} e + 3 \, {\left (B a^{2} b^{2} - A a b^{3}\right )} d e^{2} - {\left (B a^{3} b - A a^{2} b^{2}\right )} e^{3}\right )} x - 12 \, {\left ({\left (B a b^{3} - A b^{4}\right )} d^{3} - 3 \, {\left (B a^{2} b^{2} - A a b^{3}\right )} d^{2} e + 3 \, {\left (B a^{3} b - A a^{2} b^{2}\right )} d e^{2} - {\left (B a^{4} - A a^{3} b\right )} e^{3}\right )} \log \left (b x + a\right )}{12 \, b^{5}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((B*x+A)*(e*x+d)^3/(b*x+a),x, algorithm="fricas")

[Out]

1/12*(3*B*b^4*e^3*x^4 + 4*(3*B*b^4*d*e^2 - (B*a*b^3 - A*b^4)*e^3)*x^3 + 6*(3*B*b^4*d^2*e - 3*(B*a*b^3 - A*b^4)
*d*e^2 + (B*a^2*b^2 - A*a*b^3)*e^3)*x^2 + 12*(B*b^4*d^3 - 3*(B*a*b^3 - A*b^4)*d^2*e + 3*(B*a^2*b^2 - A*a*b^3)*
d*e^2 - (B*a^3*b - A*a^2*b^2)*e^3)*x - 12*((B*a*b^3 - A*b^4)*d^3 - 3*(B*a^2*b^2 - A*a*b^3)*d^2*e + 3*(B*a^3*b
- A*a^2*b^2)*d*e^2 - (B*a^4 - A*a^3*b)*e^3)*log(b*x + a))/b^5

________________________________________________________________________________________

giac [B]  time = 1.28, size = 287, normalized size = 2.33 \begin {gather*} \frac {3 \, B b^{3} x^{4} e^{3} + 12 \, B b^{3} d x^{3} e^{2} + 18 \, B b^{3} d^{2} x^{2} e + 12 \, B b^{3} d^{3} x - 4 \, B a b^{2} x^{3} e^{3} + 4 \, A b^{3} x^{3} e^{3} - 18 \, B a b^{2} d x^{2} e^{2} + 18 \, A b^{3} d x^{2} e^{2} - 36 \, B a b^{2} d^{2} x e + 36 \, A b^{3} d^{2} x e + 6 \, B a^{2} b x^{2} e^{3} - 6 \, A a b^{2} x^{2} e^{3} + 36 \, B a^{2} b d x e^{2} - 36 \, A a b^{2} d x e^{2} - 12 \, B a^{3} x e^{3} + 12 \, A a^{2} b x e^{3}}{12 \, b^{4}} - \frac {{\left (B a b^{3} d^{3} - A b^{4} d^{3} - 3 \, B a^{2} b^{2} d^{2} e + 3 \, A a b^{3} d^{2} e + 3 \, B a^{3} b d e^{2} - 3 \, A a^{2} b^{2} d e^{2} - B a^{4} e^{3} + A a^{3} b e^{3}\right )} \log \left ({\left | b x + a \right |}\right )}{b^{5}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((B*x+A)*(e*x+d)^3/(b*x+a),x, algorithm="giac")

[Out]

1/12*(3*B*b^3*x^4*e^3 + 12*B*b^3*d*x^3*e^2 + 18*B*b^3*d^2*x^2*e + 12*B*b^3*d^3*x - 4*B*a*b^2*x^3*e^3 + 4*A*b^3
*x^3*e^3 - 18*B*a*b^2*d*x^2*e^2 + 18*A*b^3*d*x^2*e^2 - 36*B*a*b^2*d^2*x*e + 36*A*b^3*d^2*x*e + 6*B*a^2*b*x^2*e
^3 - 6*A*a*b^2*x^2*e^3 + 36*B*a^2*b*d*x*e^2 - 36*A*a*b^2*d*x*e^2 - 12*B*a^3*x*e^3 + 12*A*a^2*b*x*e^3)/b^4 - (B
*a*b^3*d^3 - A*b^4*d^3 - 3*B*a^2*b^2*d^2*e + 3*A*a*b^3*d^2*e + 3*B*a^3*b*d*e^2 - 3*A*a^2*b^2*d*e^2 - B*a^4*e^3
+ A*a^3*b*e^3)*log(abs(b*x + a))/b^5

________________________________________________________________________________________

maple [B]  time = 0.00, size = 341, normalized size = 2.77 \begin {gather*} \frac {B \,e^{3} x^{4}}{4 b}+\frac {A \,e^{3} x^{3}}{3 b}-\frac {B a \,e^{3} x^{3}}{3 b^{2}}+\frac {B d \,e^{2} x^{3}}{b}-\frac {A a \,e^{3} x^{2}}{2 b^{2}}+\frac {3 A d \,e^{2} x^{2}}{2 b}+\frac {B \,a^{2} e^{3} x^{2}}{2 b^{3}}-\frac {3 B a d \,e^{2} x^{2}}{2 b^{2}}+\frac {3 B \,d^{2} e \,x^{2}}{2 b}-\frac {A \,a^{3} e^{3} \ln \left (b x +a \right )}{b^{4}}+\frac {3 A \,a^{2} d \,e^{2} \ln \left (b x +a \right )}{b^{3}}+\frac {A \,a^{2} e^{3} x}{b^{3}}-\frac {3 A a \,d^{2} e \ln \left (b x +a \right )}{b^{2}}-\frac {3 A a d \,e^{2} x}{b^{2}}+\frac {A \,d^{3} \ln \left (b x +a \right )}{b}+\frac {3 A \,d^{2} e x}{b}+\frac {B \,a^{4} e^{3} \ln \left (b x +a \right )}{b^{5}}-\frac {3 B \,a^{3} d \,e^{2} \ln \left (b x +a \right )}{b^{4}}-\frac {B \,a^{3} e^{3} x}{b^{4}}+\frac {3 B \,a^{2} d^{2} e \ln \left (b x +a \right )}{b^{3}}+\frac {3 B \,a^{2} d \,e^{2} x}{b^{3}}-\frac {B a \,d^{3} \ln \left (b x +a \right )}{b^{2}}-\frac {3 B a \,d^{2} e x}{b^{2}}+\frac {B \,d^{3} x}{b} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((B*x+A)*(e*x+d)^3/(b*x+a),x)

[Out]

1/4/b*B*x^4*e^3+1/3/b*A*x^3*e^3-1/3/b^2*B*x^3*a*e^3+1/b*B*x^3*d*e^2-1/2/b^2*A*x^2*a*e^3+3/2/b*A*x^2*d*e^2+1/2/
b^3*B*x^2*a^2*e^3-3/2/b^2*B*x^2*a*d*e^2+3/2/b*B*x^2*d^2*e+1/b^3*A*x*a^2*e^3-3/b^2*A*x*a*d*e^2+3/b*A*x*d^2*e-1/
b^4*B*x*a^3*e^3+3/b^3*B*x*a^2*d*e^2-3/b^2*B*x*a*d^2*e+1/b*B*x*d^3-1/b^4*ln(b*x+a)*A*a^3*e^3+3/b^3*ln(b*x+a)*A*
a^2*d*e^2-3/b^2*ln(b*x+a)*A*a*d^2*e+1/b*ln(b*x+a)*A*d^3+1/b^5*ln(b*x+a)*B*a^4*e^3-3/b^4*ln(b*x+a)*B*a^3*d*e^2+
3/b^3*ln(b*x+a)*B*a^2*d^2*e-1/b^2*ln(b*x+a)*B*a*d^3

________________________________________________________________________________________

maxima [B]  time = 0.82, size = 266, normalized size = 2.16 \begin {gather*} \frac {3 \, B b^{3} e^{3} x^{4} + 4 \, {\left (3 \, B b^{3} d e^{2} - {\left (B a b^{2} - A b^{3}\right )} e^{3}\right )} x^{3} + 6 \, {\left (3 \, B b^{3} d^{2} e - 3 \, {\left (B a b^{2} - A b^{3}\right )} d e^{2} + {\left (B a^{2} b - A a b^{2}\right )} e^{3}\right )} x^{2} + 12 \, {\left (B b^{3} d^{3} - 3 \, {\left (B a b^{2} - A b^{3}\right )} d^{2} e + 3 \, {\left (B a^{2} b - A a b^{2}\right )} d e^{2} - {\left (B a^{3} - A a^{2} b\right )} e^{3}\right )} x}{12 \, b^{4}} - \frac {{\left ({\left (B a b^{3} - A b^{4}\right )} d^{3} - 3 \, {\left (B a^{2} b^{2} - A a b^{3}\right )} d^{2} e + 3 \, {\left (B a^{3} b - A a^{2} b^{2}\right )} d e^{2} - {\left (B a^{4} - A a^{3} b\right )} e^{3}\right )} \log \left (b x + a\right )}{b^{5}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((B*x+A)*(e*x+d)^3/(b*x+a),x, algorithm="maxima")

[Out]

1/12*(3*B*b^3*e^3*x^4 + 4*(3*B*b^3*d*e^2 - (B*a*b^2 - A*b^3)*e^3)*x^3 + 6*(3*B*b^3*d^2*e - 3*(B*a*b^2 - A*b^3)
*d*e^2 + (B*a^2*b - A*a*b^2)*e^3)*x^2 + 12*(B*b^3*d^3 - 3*(B*a*b^2 - A*b^3)*d^2*e + 3*(B*a^2*b - A*a*b^2)*d*e^
2 - (B*a^3 - A*a^2*b)*e^3)*x)/b^4 - ((B*a*b^3 - A*b^4)*d^3 - 3*(B*a^2*b^2 - A*a*b^3)*d^2*e + 3*(B*a^3*b - A*a^
2*b^2)*d*e^2 - (B*a^4 - A*a^3*b)*e^3)*log(b*x + a)/b^5

________________________________________________________________________________________

mupad [B]  time = 0.07, size = 268, normalized size = 2.18 \begin {gather*} x\,\left (\frac {B\,d^3+3\,A\,e\,d^2}{b}+\frac {a\,\left (\frac {a\,\left (\frac {A\,e^3+3\,B\,d\,e^2}{b}-\frac {B\,a\,e^3}{b^2}\right )}{b}-\frac {3\,d\,e\,\left (A\,e+B\,d\right )}{b}\right )}{b}\right )-x^2\,\left (\frac {a\,\left (\frac {A\,e^3+3\,B\,d\,e^2}{b}-\frac {B\,a\,e^3}{b^2}\right )}{2\,b}-\frac {3\,d\,e\,\left (A\,e+B\,d\right )}{2\,b}\right )+x^3\,\left (\frac {A\,e^3+3\,B\,d\,e^2}{3\,b}-\frac {B\,a\,e^3}{3\,b^2}\right )+\frac {\ln \left (a+b\,x\right )\,\left (B\,a^4\,e^3-3\,B\,a^3\,b\,d\,e^2-A\,a^3\,b\,e^3+3\,B\,a^2\,b^2\,d^2\,e+3\,A\,a^2\,b^2\,d\,e^2-B\,a\,b^3\,d^3-3\,A\,a\,b^3\,d^2\,e+A\,b^4\,d^3\right )}{b^5}+\frac {B\,e^3\,x^4}{4\,b} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((A + B*x)*(d + e*x)^3)/(a + b*x),x)

[Out]

x*((B*d^3 + 3*A*d^2*e)/b + (a*((a*((A*e^3 + 3*B*d*e^2)/b - (B*a*e^3)/b^2))/b - (3*d*e*(A*e + B*d))/b))/b) - x^
2*((a*((A*e^3 + 3*B*d*e^2)/b - (B*a*e^3)/b^2))/(2*b) - (3*d*e*(A*e + B*d))/(2*b)) + x^3*((A*e^3 + 3*B*d*e^2)/(
3*b) - (B*a*e^3)/(3*b^2)) + (log(a + b*x)*(A*b^4*d^3 + B*a^4*e^3 - A*a^3*b*e^3 - B*a*b^3*d^3 + 3*A*a^2*b^2*d*e
^2 + 3*B*a^2*b^2*d^2*e - 3*A*a*b^3*d^2*e - 3*B*a^3*b*d*e^2))/b^5 + (B*e^3*x^4)/(4*b)

________________________________________________________________________________________

sympy [B]  time = 0.73, size = 221, normalized size = 1.80 \begin {gather*} \frac {B e^{3} x^{4}}{4 b} + x^{3} \left (\frac {A e^{3}}{3 b} - \frac {B a e^{3}}{3 b^{2}} + \frac {B d e^{2}}{b}\right ) + x^{2} \left (- \frac {A a e^{3}}{2 b^{2}} + \frac {3 A d e^{2}}{2 b} + \frac {B a^{2} e^{3}}{2 b^{3}} - \frac {3 B a d e^{2}}{2 b^{2}} + \frac {3 B d^{2} e}{2 b}\right ) + x \left (\frac {A a^{2} e^{3}}{b^{3}} - \frac {3 A a d e^{2}}{b^{2}} + \frac {3 A d^{2} e}{b} - \frac {B a^{3} e^{3}}{b^{4}} + \frac {3 B a^{2} d e^{2}}{b^{3}} - \frac {3 B a d^{2} e}{b^{2}} + \frac {B d^{3}}{b}\right ) + \frac {\left (- A b + B a\right ) \left (a e - b d\right )^{3} \log {\left (a + b x \right )}}{b^{5}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((B*x+A)*(e*x+d)**3/(b*x+a),x)

[Out]

B*e**3*x**4/(4*b) + x**3*(A*e**3/(3*b) - B*a*e**3/(3*b**2) + B*d*e**2/b) + x**2*(-A*a*e**3/(2*b**2) + 3*A*d*e*
*2/(2*b) + B*a**2*e**3/(2*b**3) - 3*B*a*d*e**2/(2*b**2) + 3*B*d**2*e/(2*b)) + x*(A*a**2*e**3/b**3 - 3*A*a*d*e*
*2/b**2 + 3*A*d**2*e/b - B*a**3*e**3/b**4 + 3*B*a**2*d*e**2/b**3 - 3*B*a*d**2*e/b**2 + B*d**3/b) + (-A*b + B*a
)*(a*e - b*d)**3*log(a + b*x)/b**5

________________________________________________________________________________________